How to extract substring matching the pattern using JQuery

Question

I would like to extract full name from the string using regular expression. How can i do that? This code gives me empty value of result. What's wrong?

var p = '№ 46/20 John Smith Newmore 23.01.2020';
var result = p.match(/^([a-zA-Z0-9]+|[a-zA-Z0-9]+\s{1}[a-zA-Z0-9]{1,}|[a-zA-Z0-9]+\s{1}[a-zA-Z0-9]{3,}\s{1}[a-zA-Z0-9]{1,})$/);

My expected result matches the regular expression:

Existing data - string: '№ 46/20 John Smith Newmore 23.01.2020'

Expected result: 'John Smith Newmore'

p.replace(/[^а-яА-ЯёЁa-zA-Z ]+/g,'').trim() if you ask for Russian ones. Or p.replace(/[^\u0400-\u04FFa-zA-Z ]+/g,'').trim() to handle any Cyrillic chars. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Mar 5, 2020 at 10:19
@WiktorStribiżew i got the same "Uncaught SyntaxError: Invalid regular expression: /[^Р°-СЏРђ-РЇС‘РЃa-zA-Z ]+/: Range out of order in character class" — Vytsalo
– Vytsalo, Commented Mar 5, 2020 at 10:21
That's a problem with your file encoding. But p.replace(/[^\u0400-\u04FFa-zA-Z ]+/g,'').trim() will work with all Cyrillic chars. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Mar 5, 2020 at 10:23

user3766508 · Accepted Answer · 2020-03-05 06:05:23Z

1

var str = '№ 46/20 John Smith Newmore 23.01.2020';

console.log(str.replace(/[^a-zA-Z ]/g, ""));

answered Mar 5, 2020 at 6:05

user3766508

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Comments

Mamun · Accepted Answer · 2020-03-05 06:04:22Z

0

You can try matching anything between number followed by space and space followed by number using RegEx lookbehind and lookahead:

var p = '№ 46/20 John Smith Newmore 23.01.2020';
var result = p.match(/(?<=\d+ ).+(?= \d+)/)[0];
console.log(result);

edited Mar 5, 2020 at 6:04

answered Mar 5, 2020 at 5:59

Mamun

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