Append string to words in snippets

Question

I am currently working on some Python snippets for VSCode using JavaScript regular expressions and I'd like to have one like :

Given

var1, var2, var3

Produce

self.var1 = var1
self.var2 = var2
self.var3 = var3

I currently know how to replace commas with line jump but not how to replace each word with another string. I'm pretty bad at regular expressions so it doesn't help. I think I'll need something that does the following :

var1, var2 -> self.var1 = var1, self.var2 = var2

Thanks for your help

Edit : From suggestions in comments I tried this : /(.*,)/self.$0 = $0/ It obviously doesn't work for several reasons : it matches all strings up to the last comma. VSCode doesn't give access to "\w" but i don't see how it would help. Other thing I tested that couldn't work either since I'm looking for duplicating each of the words : /(.*)/self.$0 = $0/

And since I didn't post it, here is the comme replacement by a new line : /[,]/\n/g

Edit2 (updated) : From comment suggestions I tried : /(.*?)(?:, |$)/self.$1 = $1\n/g which leads to almost perfect result :

toto, titi, tata

leads to

self.toto = toto
self.titi = titi
self.tata = tata
self. =

I actually don't know how to try anything. As I said, I can replace commas with line jump (which is quite easy) but I don't know where to start. I'd like to select the beginning of each word and replace it with "self." as well as duplicating each word and appending an "=" before. But I don't know how to do it — Ricocotam
– Ricocotam, Commented Mar 10, 2020 at 14:52
Ok, so this doesn't help at all since I already went through the entire regex doc of JS and Python. I want ti duplicate a word and insert string before/after it. None of the thing I read answers this nor leads to an idea. — Ricocotam
– Ricocotam, Commented Mar 10, 2020 at 15:08
Ok so it was not clear at all since you linked something to add string at the end of a line. I tested what you explained but it does not work since I am matching any word, just as you said. But what I want is to duplicate each of the words : "toto, tata, titi" should give "toto toto, tata tata, titi titi" and it gives "toto, tata, titi toto, tata, titi" — Ricocotam
– Ricocotam, Commented Mar 10, 2020 at 15:16
I think we have something here, thanks @HarmvanderWal. Sadly it doesn't exactly work. I'll update the question — Ricocotam
– Ricocotam, Commented Mar 10, 2020 at 15:31

rioV8 · Accepted Answer · 2020-03-10 23:49:13Z

3

Add the following to your python.json snippet file

  "var-init": {
    "prefix": "varinit",
    "body": [
      "${1/([\\w_]+)(?:[,\\s]|$)/self.$1 = $1\n/g}",
      "$0"
    ],
    "description": "var initialisation"
  }

Type the prefix: varinit
Press Tab
Type the variables you want separated by , with or without spaces: titi,tata,toto
Press Tab

Result

self.titi = titi
self.tata = tata
self.toto = toto

And the cursor on the next line.

Edit

A simplification of the regex and using the tip from Mark about the if-replacement ${2:+\n}

"${1/([\\w_]+)([, ])*/self.$1 = $1${2:+\n}/g}"

now the variables can be separated with spaces or ,

edited Mar 10, 2020 at 23:49

answered Mar 10, 2020 at 16:35

rioV8

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2 Comments

Mark Over a year ago

Looks familiar... I would suggest ` "${1/\\s*([^,]+)(,)*/self.$1 = $1${2:+\n}/g}",` as the regex is a little simpler and it doesn't add an extra newline after the last variable. And the spaces are handled much better. I get spaces added to the beginning of subsequent lines with your code.

Mark Over a year ago

It is also easy to modify this to where the variables are already listed and selected. If that is a use case for the OP. For more complicated cases of using variable numbers of arguments in a class constructor snippet see stackoverflow.com/questions/53998252/… and for a class initializer see stackoverflow.com/questions/58225204/…

Wiktor Stribiżew · Accepted Answer · 2020-03-10 16:01:32Z

0

You may use

Find What: \s*([^,\s]+)(?:,|$)
Replace With: self.$1 = $1\n

See the regex demo.

Details

\s* - 0 or more whitespaces
([^,\s]+) - capturing group 1: one or more chars other than whitespace and comma
(?:,|$) - a non-capturing group matching , or end of line.

answered Mar 10, 2020 at 16:01

Wiktor Stribiżew

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