I need to do bitwise OR of two binary strings.
For example, if the binary strings are "110001" and "101101", then I need the result as "111101".
How can I do this in Swift ?
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1 Answer
You can convert it first into Int
let a = Int("110001", radix: 2)!
let b = Int("101101", radix: 2)!
let c = a | b
let stringResult = String(c, radix: 2, uppercase: false)
More info:
8 Comments
Saleh Masum
Thank you for the answer. Can you tell me how can I do this for very big binary string. For example a binary string like this : "1001101111101011011100101100100110111011111011000100111100111110111101011011011100111001100011111010". Current solution can't convert this number which is pretty long.
theoriginalbit
you will want to iterate over the characters in both of your input strings and if either character is
"1" then you would write "1" to the output string, otherwise you would write "0". Iterating both strings at the same time can be achieved with zip assuming both input strings are the same length.
Joakim Danielson
@SalehMasum That string is 100 char long, what would it represent? Maybe you should divide it into smaller chunks first before converting it.
Saleh Masum
@theoriginalbit yes it is achievable by a for loop but the problem is it takes too long that's why I am looking for alternatives. A BigInteger class can do this job but swift does not have it.
theoriginalbit
@SalehMasum when you say "takes too long" what exactly is your definition of "too long". I was able to just perform a measure with a 500 char long string and it took an average of 0.005 seconds.
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