PHP Foreach on array of objects

Question

Why, if I have array of objects like this:

class testClass {

    private $_x = 10;

    public function setX($x) {
       $this->_x = $x;
    }

    public function writeX() {
        echo $this->_x . '<br />';
    }

}

$t = array();

for ($i = 0; $i < 10; $i++) {
    $t[] = new testClass();
}

print_r($t);

I can iterate by foreach like this:

foreach ($t as $tt) {
    $tt->y = 7;
    $tt->setX($counter);
    $counter+=100;
}

print_r($t);

Or this:

foreach ($t as &$tt) {
    $tt->y = 7;
    $tt->setX($counter);
    $counter+=100;
}

print_r($t);

And result will be equal? But if i have scalar values in array, they can only be modified by ($arr as &$v), $v only by reference ?

Denis de Bernardy · Accepted Answer · 2011-05-20 13:08:35Z

3

It depends on whether you're using PHP5 or an earlier version.

In PHP5, same thing because it is an array of objects. (Not the same thing for other types.)

In PHP4, not the same thing. (But then again, the second one will complain about a syntax anyway.)

answered May 20, 2011 at 13:08

Denis de Bernardy

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4 Comments

Guy Fawkes Over a year ago

So I must just remember this behaviour "as is"?

Denis de Bernardy Over a year ago

Or, you might want to read this: php.net/manual/en/language.oop5.references.php

Guy Fawkes Over a year ago

Where I can find information about my question in this manual?

Denis de Bernardy Over a year ago

> An object variable doesn't contain the object itself as value anymore. It only contains an object identifier which allows object accessors to find the actual object. When an object is sent by argument, returned or assigned to another variable, the different variables are not aliases: they hold a copy of the identifier, which points to the same object.

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