How to make a 2d array of tuples in python?

Question

I want to make a 2D array of 2-tuples of fixed dimension (say 10x10).

e.g

[[(1,2), (1,2), (1,2)],
 [(1,2), (1,2), (1,2)],
 [(1,2), (1,2), (1,2)]]

There are also two ways that I'd like to generate this array:

An array like the example above where every element is the same tuple
An array which I populate iteratively with specific tuples (possibly starting with an empty array of fixed size and then using assignment)

How would I go about doing this? For #1 I tried using numpy.tiles:

>>> np.tile(np.array([1,2]), (3, 3))
array([[1, 2, 1, 2, 1, 2],
       [1, 2, 1, 2, 1, 2],
       [1, 2, 1, 2, 1, 2]])

But I can't seem to copy it across columns, the columns are just concatenated.

i.e instead of:

[[[1,2], [1,2], [1,2]],
 [[1,2], [1,2], [1,2]],
 [[1,2], [1,2], [1,2]]]

kederrac · Accepted Answer · 2020-03-19 06:48:25Z

3

you can use numpy.full:

numpy.full((3, 3, 2), (1, 2))

output:

array([[[1, 2],
        [1, 2],
        [1, 2]],

       [[1, 2],
        [1, 2],
        [1, 2]],

       [[1, 2],
        [1, 2],
        [1, 2]]])

answered Mar 19, 2020 at 6:48

kederrac

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Comments

gamesun · Accepted Answer · 2020-03-19 06:39:41Z

0

for <1> you can generate like this

[[(1,2)] * 3]*3
# get [[(1, 2), (1, 2), (1, 2)], [(1, 2), (1, 2), (1, 2)], [(1, 2), (1, 2), (1, 2)]]

answered Mar 19, 2020 at 6:39

gamesun

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for <2> could you give a sample?

Joran Beasley · Accepted Answer · 2020-03-19 06:44:27Z

0

numpy.zeros((3,3,2))

I guess would work (but its not tuples its lists...)

answered Mar 19, 2020 at 6:44

Joran Beasley

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