1 

const count = () => {
  for (let i = 1; i <= 5; i++) {
    if ((2 + 2) == 4) {
      return (' Bla ')
    }
  }
};

console.log(count());

The output: 'Bla' And I was expecting: 'Bla' 'Bla' 'Bla' 'Bla' 'Bla'.

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2
  • Put console log inside the loop or else return a array of values and print them. Commented Mar 20, 2020 at 12:16
  • for i=1, the codition gets true and return you the value Commented Mar 20, 2020 at 12:19

1 Answer 1

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1

In the first iteration, the function returns, so the loop does not continue. You could instead call console.log from within the loop directly:

const count = () => {
  for (let i = 1; i <= 5; i++) {
    if ((2 + 2) == 4) {
      console.log(' Bla ')
    }
  }
};

count();

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