Python & Selenium: Unable to click A HREF in a frame

Question

I'm having issues clicking an A HREF on a website. Please see below for an inspection on the A HREF and the steps that I've tried. Any assistance is greatly appreciated.

I've tried:

 browser.switch_to.default_content()
 frames = browser.find_elements_by_tag_name('frame')
 browser.switch_to.frame(frames[1])
 browser.find_element_by_xpath("//a[contains(@href,'Home')]").click()

and also:

 browser.find_element_by_xpath('//a[@href="javascript:openWorkFrame(\'/web/entry/en/websys/webArch/topPage.cgi\');"]').click()

Does this answer your question? Select iframe using Python + Selenium — AMC
– AMC, Commented Mar 20, 2020 at 22:12

ThePyGuy · Accepted Answer · 2020-03-20 22:00:47Z

2

Try to switch to your first frame using browser.switch_to_frame(element) and then use below xpath to click on a link

frame = browser.find_element_by_name('header')
browser.switch_to_frame(frame)
browser.find_element_by_xpath("//a/span").click()
browser.switch_to_default_content()

edited Mar 20, 2020 at 22:00

ThePyGuy

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answered Mar 20, 2020 at 21:52

SeleniumUser

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Comments

Agate · Accepted Answer · 2020-03-20 20:34:59Z

0

Maybe you could try this XPath expression?

xpath_expr = "//a/span[text() = 'Home']/.."
browser.find_element_by_xpath(xpath_expr).click()

Basically, find the span element with text = "Home", then select its parent (the link).

edited Mar 20, 2020 at 20:34

answered Mar 20, 2020 at 20:29

Agate

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2 Comments

Kyocera Alerts Over a year ago

i got the following message: selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//a/span[text() = 'Home']/.."}

Agate Over a year ago

Sorry then, I'm not familiar enough with Selenium, maybe the frame is getting in the way? I'd recommend creating a simplifiede test case by copying the basic structure of your DOM, and share it here so people can experiment with XPath expressions.

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