How to access url path in django view

Question

How can I access the url in a Django view. I have a view handling following 5 urls:

localhost:8000/standings/
localhost:8000/standings/q1
localhost:8000/standings/q2
localhost:8000/standings/q3
localhost:8000/standings/q4

and my view is

class StandingsView(LoginRequiredMixin, TemplateView):
    template_name = 'standings.html'

Based on q1, q2, q3, q4 or None in the url path, I have to query data from the db and render to the given template.

Please suggest on how such scenarios can be handled.

Can you share the url config for this view?

Iain Shelvington
– Iain Shelvington

2020-03-25 08:00:30 +00:00
Commented Mar 25, 2020 at 8:00 — Iain Shelvington
– Iain Shelvington, Commented Mar 25, 2020 at 8:00

willeM_ Van Onsem · Accepted Answer · 2020-03-25 08:05:34Z

4

You can access the path with self.request.path:

class StandingsView(LoginRequiredMixin, TemplateView):
    template_name = 'standings.html'

    def get_context_data(self, *args, **kwargs):
        context = super().get_context_data()
        path = self.request.path
        # …
        return context

But processing the path might be cumbersome and error prone. You can define five urls here in the urls.py and inject values in the kwargs, like:

from django.urls import path

from app.views import StandingsView

urlpatterns = [
    path('standings/', StandingsView.as_view(), kwargs={'q': None}),
    path('standings/q1', StandingsView.as_view(), kwargs={'q': 1}),
    path('standings/q2', StandingsView.as_view(), kwargs={'q': 2}),
    path('standings/q3', StandingsView.as_view(), kwargs={'q': 3}),
    path('standings/q4', StandingsView.as_view(), kwargs={'q': 4})
]

Then you can access the added kwargs in self.kwargs['q']:

class StandingsView(LoginRequiredMixin, TemplateView):
    template_name = 'standings.html'

    def get_context_data(self, *args, **kwargs):
        context = super().get_context_data()
        q = self.kwargs['q']
        # …
        return context

You might however want to take a look at a ListView [Django-doc] that can implement most of the boilerplate logic.

answered Mar 25, 2020 at 8:05

willeM_ Van Onsem

482k33 gold badges483 silver badges624 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Saurabh Over a year ago

What if I want to send the other urls(i.e. except the one that is called out) to the template to be shown as links on the UI? I can explicitly define the other urls and add them to a list and update the context with this list but that doesn't seems to be a good approach.

Collectives™ on Stack Overflow

How to access url path in django view

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related