How to convert a tuple into a numpy array?

Question

I have a tuple that contains a numpy array that I want to convert into just the numpy array. The current tuple is:

Tup = (array([ 7500, 10476, 10643, 13683, 14761]),)

i've tried using the np.asarray module but when I do this it just adds an array around the tuple instead of removing it as seen below:

Tup= np.asarray(Tup)
print(Tup)
Output: array([[ 7500, 10476, 10643, 13683, 14761]])

How would I convert Tup into just an array. My ideal output would be:

[7500, 10476, 10643, 13683, 14761]

Just select the first element of the tuple Tup[0]

tomjn
– tomjn

2020-03-26 13:30:50 +00:00
Commented Mar 26, 2020 at 13:30 — tomjn
– tomjn, Commented Mar 26, 2020 at 13:30
How about Tup[0]? Or do you actually want a list?

Michael Butscher
– Michael Butscher

2020-03-26 13:31:26 +00:00
Commented Mar 26, 2020 at 13:31 — Michael Butscher
– Michael Butscher, Commented Mar 26, 2020 at 13:31

AKX · Accepted Answer · 2020-03-26 13:30:58Z

2

You seem to have an 1-tuple containing an array as the single element; just index with zero to get the first (zeroth) element to select the array:

arr = Tup[0]

To get to a bare Python list (as per your "ideal output"),

arr = list(Tup[0])

should do the trick.

answered Mar 26, 2020 at 13:30

AKX

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Suraj · Accepted Answer · 2020-03-26 13:32:19Z

1

list(Tup[0])

Extract the numpy array from the tuple and convert it into a list

answered Mar 26, 2020 at 13:32

Suraj

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Comments

Sumit Bishnoi · Accepted Answer · 2021-09-03 09:13:20Z

1

It's actually bit easier. What you need to do is simply use this code & it's done. array_from_tuple = np.array(tuple_name) where tuple_name is the name assigned to the object. For more features you can refer to this syntax:

numpy.array( object, dtype = None, *, copy = True, order = ‘K’, subok = False, ndmin = 0 )

Thanks for A2A! Keep exploring!

answered Sep 3, 2021 at 9:13

Sumit Bishnoi

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