Insert input to exe program with linux script

Question

I got a script that asks 1000 times for input of 1-5, it looks like this:

insert1:

insert2:

insert3:

insert4:

insert5: //and again 1-5

insert 1: ...in total it will get 1000 inputs

I want to write a one line script that will run the script I just described, it will insert the input that needed each time. this is what I tried:

#!/bin/bash
./my_script.exe  -l | for i in {1..200}; do for j in {1..5}; do j; done; done

Remember, a pipe connects the output of the thing on the left to the input of the thing on the right. (And j just runs the command j, it doesn't have anything to do with the contents of the variable expanded with $j). — Charles Duffy
– Charles Duffy, Commented Jan 4, 2024 at 16:31

Rojo · Accepted Answer · 2024-01-04 16:25:16Z

1

You are nearly there, but do it the other way around:

for i in {1..200} ; do
    for j in {1..5} ; do
        echo $j
    done
done | ./myscript.exe -l

You can put a # before the | to comment it out and see what the script sends to your program.

You need to differentiate between parameters which are specified after the program name like this:

program param1 param2 param3

and inputs, which a program gets by reading its stdin and are supplied like this:

printf "input1\ninput2\ninput3\n" | program

Alternative version of second command:

{ echo input1; echo input2; echo input3; } | program

edited Jan 4, 2024 at 16:25

Rojo

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answered Mar 29, 2020 at 19:07

Mark Setchell

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1 Comment

tripleee Over a year ago

@Rojo There's nothing wrong with your edit per se; but there also was nothing wrong with the original code. If you have a reason for changing the for loops, can you please share it?

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