why the if statement did not print out the string? cpp

Question

I want to print the even and odd in a string rather than in binary for true false | 1 / 0; Why the output still print the boolean value?

int main() {
    printf("enter the two numbers\n");
    int a;
    int b;
    cin >> a >> b;

    string arr[9] = {"one","two","three","four","five","six","seven","eight","nine"}; 
    for (int i = a; i <= b; i++)
    {
        if(i <=9){
           cout << arr[i-1] << "\n";
        }else{
           cout << ( i%2 == 0)? "even" : "odd"; // print out 1/0 but did not print out the even and odd
           cout << "\n";
        }
    }

    return 0;
}

output:

enter the two numbers
9 16
nine
1
0
1
0
1
0
1

Compiler warnings are helpful: "warning: third operand of conditional expression has no effect" (wandbox.org/permlink/2mCAy4nyNZ5LJ93x). — Kerrek SB
– Kerrek SB, Commented Mar 31, 2020 at 16:48

stark · Accepted Answer · 2020-03-31 16:47:29Z

4

You are missing parens to enclose the expression. The ternary has lower precedence than <<.

cout << (( i%2 == 0)? "even" : "odd");

answered Mar 31, 2020 at 16:47

stark

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3 Comments

Pete Becker Over a year ago

Also, the parentheses around i%2 == 0 aren't needed.

stark Over a year ago

@PeteBecker True, but those of us who have to look at the chart on our wall every time would be tempted to put them in anyway.

Pete Becker Over a year ago

@stark -- (I (understand (what (you're talking about)))).

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