I looked online and every method for extracting numbers from strings uses the
[int(word) for word in a_string.split() if word.isdigit()] method,
however when I run the code below, it does not extract the number 45
test = "ON45"
print(test)
print([int(i) for i in test.split() if i.isdigit()])
This is what python prints
ON45
[]
The second list is empty, it should be [45] which I should be able to access as integer using output_int = test[0]
Following works:
import re
test = "ON45"
print(test)
print(str(list(map(int, re.findall(r'\d+', test)))))
If you want to get the individual digits
print([int(i) for i in test if i.isdigit()])
output
[4, 5]
If you want to get concatenated numbers
import re
print(re.findall(r'[0-9]+', test))
output
['45']
hope it helps
str.split with no arguments splits a string on whitespace, which your string has none of. Thus you end up with i in your list comprehension being ON45 which does not pass isdigit(); hence your output list is empty. One way of achieving what you want is:
int(''.join(i for i in test if i.isdigit()))
Output:
45
You can put that in a list if desired by simply enclosing the int in [] i.e.
[int(''.join(i for i in test if i.isdigit()))]
You can iterate through the characters in each string from the list resulting from the split, filter out the non-digit characters, and then join the rest back into a string:
test = "ON45"
print([int(''.join(i for i in s if i.isdigit())) for s in test.split()])
This outputs:
[45]
Yes, because string.split() splits on space, which you don't have in the original string. With the string "ON 24" it'd work just fine.
splitbut the way iit was supposed to be...