Find string from array

Question

So I have this piece of code that has given me some headache. This is a function. names is an array that contains names. I ask user input to search and then I want to check if the name contains the string from search. I don't know what to do and didn't find anything that helped me (i'm probably just stupid).

bool contains(string*& names, string*& search){
for(unsigned int j = 0; j < names.length(); j++){
    if(names[j].find(search) != string::npos){
        return true;
    }
}
return false;

}

Shika · Accepted Answer · 2020-04-05 13:24:33Z

1

The problem is that you need to pass the function find an array, not names[j], so changing names[j] with names works just fine. Also you don't need to make the strings pointers since you don't change them. This code works just fine for me:

bool contains(string names, string search){
for(unsigned int j = 0; j < names.length(); j++){
    if(names.find(search) != string::npos){
        return true;
    }
}
return false;

}

answered Apr 5, 2020 at 13:24

Shika

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