Plot a generic function in Python

Question

I have the following mathematical function in Python:

y = max(0, |x| - epsilon)

To plot it I have done the usual

import matplotlib.pyplot as plt
import numpy as np

x = np.linspace(-100,100,400)
y = np.maximum(0, np.absolute(x) - 10)

plt.plot(x,y)
plt.show()

but I want to plot it without assigning any value to epsilon as shown in the picture

What would you want to plot? y is an entire family of functions, one function for each value of epsilon. Looking at it anther way, y is a higher-order function whose limit as epsilon approaches 0 is y = |x|. — chepner
– chepner, Commented Apr 8, 2020 at 12:13

Tristan Nemoz · Accepted Answer · 2020-04-08 12:01:48Z

1

If you know the value of epsilon, then you can do it using plt.xticks:

epsilon = 10
x = np.linspace(-100, 100, 10000)
y = np.maximum(0, np.absolute(x) - epsilon)
plt.figure()
plt.plot(x, y)
plt.xticks([-epsilon, epsilon], ["$-\\varepsilon$", "$\\varepsilon$"])
plt.plot()

If you don't, then you can just determine its value using y:

epsilon = x[y == 0][-1]

And then applying the code above.

answered Apr 8, 2020 at 12:01

Tristan Nemoz

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