ASP.NET MVC return PartialViewResult

Question

I made a form with @using(Ajax.BeginForm){}. It posts to a method in my controller that returns a PartialViewResult. It works fine when everything is valid, but what should I return if it's not (e.g., the modelstate is not valid)? How Ajax.BeginForm can manage the error? What I return to manage the Failure?

@using(Ajax.BeginForm("Create", "Room", new AjaxOptions { HttpMethod="POST",
UpdateTargetId="formRoom", InsertionMode= InsertionMode.Replace, onFailure =??})) {

public PartialViewResult Create(Movie mov)
{
        if (ModelState.IsValid)
        {
            db.Save(mov);
            return PartialView("CreateResult", mov);
        }
        return null;            
}

Thanks!

Richard Ev · Accepted Answer · 2013-08-29 16:03:38Z

3

You may return another View.

e.g. return PartialView("MyErrorView");

edited Aug 29, 2013 at 16:03

Richard Ev

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answered May 24, 2011 at 17:15

kanchirk

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1 Comment

kanchirk Over a year ago

For Ajax Calls you can also return JSON like "return Json(new { Result = "Failure", Message = "Model Invalid"},JsonRequestBehavior.AllowGet); and parse this result in the success/failure ajax call.

slfan · Accepted Answer · 2011-05-24 17:26:50Z

1

Just return Create action with the model to display the errors (the same as you returned on your get):

    [HttpPost]
    public PartialViewResult PartialCreate(Album album)
    {
        if (ModelState.IsValid)
        {
            db.Albums.Add(album);
            db.SaveChanges();
            return PartialView("Index");
        }

        ViewBag.GenreId = new SelectList(db.Genres, "GenreId", "Name", album.GenreId);
        ViewBag.ArtistId = new SelectList(db.Artists, "ArtistId", "Name", album.ArtistId);
        return PartialView(album);
    }

edited May 24, 2011 at 17:26

answered May 24, 2011 at 17:16

slfan

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6 Comments

elranu Over a year ago

you cannot return that, you cannot convert it. Try to compile it.

slfan Over a year ago

Just made a sample. It compiles without any errors. Or is it because the Ajax.BeginForm? I'll try that as well.

elranu Over a year ago

before you put return View();

slfan Over a year ago

ah, sorry, that was because I didn't see in the first place that you used a PartialView. I had already changed it when you added your comment. Does it work now?

elranu Over a year ago

yes... but I just edit my question... that was not what I intend to ask

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