Pattern match parameters to function calls Python?

Question

I'm writing a python function that calls a function based on a parameter it takes. It looks something like this:

def match(parameter):
  if parameter == 'fun1':
    fun1()
  elif parameter == 'fun2':
    fun2()
  elif parameter == 'fun3':
    fun3()

All those functions being called are then defined below the match function. Is there a more efficient way to organize the match function? I can't find anything about pattern matching with functions, but could a data structure of some sort work?

Thanks for the help.

Gabio · Accepted Answer · 2020-04-10 16:29:59Z

2

You can create a dictionary which stores the mapping between the function and the parameter value to call it.

For example:

def fun1():
    print("I am fun1")


def fun2():
    print("I am fun2")

funcs_mapping = {"fun1":fun1, "fun2":fun2}

def match(parameter):
  if parameter in funcs_mapping:
      funcs_mapping[parameter]()

edited Apr 10, 2020 at 16:29

answered Apr 10, 2020 at 16:21

Gabio

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7 Comments

abhinonymous Over a year ago

different functions may have different arguments

Mark Over a year ago

How do you know that @abhinonymous

Carcigenicate Over a year ago

@abhinonymous Then you can wrap each function in a lambda or a partial before storing it in the dictionary (wait, you're not the OP).

Gabio Over a year ago

@abhinonymous According to OP's question, the functions don't receive any params.

Mark Over a year ago

One difference between this code and OPs is how it handles unknown keys. The OP just returns None, this will raise an exception.

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