how to remove item from array list in kotlin

Question

data class RideDate(var enddate: String? = null,var startdate: String? = null) 



 fun main(args: Array<String>) {
var listOfRideDate = mutableListOf<RideDate>();
val date1 = RideDate()
date1.startdate = "2018-11-05 00:00:00 +0000"
date1.enddate = "2018-11-06 23:59:59 +0000"
listOfRideDate.add(date1)

val date2 = RideDate()
date2.startdate = "2020-01-20 00:00:00 +0000"
date2.enddate = "2020-02-20 00:00:00 +0000"
listOfRideDate.add(date2)

val date3 = RideDate()
date3.startdate = "2020-03-20 00:00:00 +0000"
date3.enddate = "2020-03-20 00:00:00 +0000"
listOfRideDate.add(date3)

val date4 = RideDate()
date4.startdate = "2020-04-20 00:00:00 +0000"
date4.enddate = "2020-04-20 00:00:00 +0000"
listOfRideDate.add(date4)

val date5 = RideDate()
date5.startdate = "2020-11-20 00:00:00 +0000"
date5.enddate = "2020-11-20 00:00:00 +0000"
listOfRideDate.add(date5)


for (i in 0..listOfRideDate.size -1) {
    // we have to remove 2018-11-05 00:00:00 +0000 and 2018-11-06 23:59:59 +0000  from list 
    println(listOfRideDate.get(i).startdate + " and " + listOfRideDate.get(i).enddate)
}

}

This is my data class and the main method I have added item RideDate of startDate and endDate manually I want delete item dynamically if data contains date1.startdate = "2018-11-05 00:00:00 +0000" date1.enddate = "2018-11-06 23:59:59 +0000"

so that I can ignore it please help me how to delete the item from array list in kotlin

Animesh Sahu · Accepted Answer · 2020-04-13 08:17:36Z

10

You can use removeAll to remove element from original list if it matches the predicate.

listOfRideDate.removeAll {
    it.startdate == "2018-11-05 00:00:00 +0000" && it.enddate == "2018-11-06 23:59:59 +0000"
}

Or you can filter by creating a new list with filtered items as suggested by Johann Kexel

val filtertedList = listOfRideDate.filter {
    it.startdate == "2018-11-05 00:00:00 +0000" && it.enddate == "2018-11-06 23:59:59 +0000"
}

answered Apr 13, 2020 at 8:17

Animesh Sahu

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Comments

Johann Kexel · Accepted Answer · 2020-04-13 08:27:34Z

2

You can use filter in your case

val filtertedList = listOfRideDate.filter { element -> someLogik(element)}

Refer also to the following page

Filtering Kotlinlang

edited Apr 13, 2020 at 8:27

answered Apr 13, 2020 at 8:03

Johann Kexel

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4 Comments

MARSH Over a year ago

can you please help me where I will add this code I am really new in this function what condition and how I will apply here someLogik(element)

MARSH Over a year ago

how to apply a filter for the start date and end date please help me in this?

Animesh Sahu Over a year ago

@MARSH do you want to remove element from original list or want to create a new filtered one?

Johann Kexel Over a year ago

someLogik was just an example and symbolizes a function which returns a Boolean and which you can define on yourself. For example fun nonNull(element:RideDate) = element != null . You can use this filtering logic instead or after your foreach loop.

Kasım Özdemir · Accepted Answer · 2020-04-13 08:42:10Z

2

Like this:

loop@ for (i in 0 until listOfRideDate.size) {
        // we have to remove 2018-11-05 00:00:00 +0000 and 2018-11-06 23:59:59 +0000  from list
        if (listOfRideDate.get(i).startdate == "2018-11-05 00:00:00 +0000" &&  listOfRideDate.get(i).enddate == "2018-11-06 23:59:59 +0000"){
            listOfRideDate.removeAt(i)
            break@loop
        }
    }

or

listOfRideDate.removeIf {
     it.startdate == "2018-11-05 00:00:00 +0000" &&  it.enddate == "2018-11-06 23:59:59 +0000"
}

edited Apr 13, 2020 at 8:42

answered Apr 13, 2020 at 8:00

Kasım Özdemir

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7 Comments

MARSH Over a year ago

its show Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 4, Size: 4

Johann Kexel Over a year ago

you cannot remove something within a loop. If you want to change your current list, you have to first save your element(s) within the loop and then use remove(element) or removeAll(elements) on the collection (Or of course also removeAt(index)) outside the loop

Kasım Özdemir Over a year ago

No, you can, Just need to stop for loop.

Kasım Özdemir Over a year ago

Right, you can remove one item

Johann Kexel Over a year ago

Sure you can do this, if you only want to remove one element.

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