Scala variable type mismatch?

Question

class New {

  val x : Option[String] = "abc"
  val y : String = "abc"

  if(x == y) "YES" else "No"

}

  **Error:(5, 28) type mismatch;
  found   : String("abc")
  required: Option[String]
  val x : Option[String] = "abc"**

I am facing above type mismatch error. Can someone help to resolve above error?

Considering that you are facing such issues, I will advise you to learn Scala in a more structured manner. I suggest reading the book Essential Scala. You can download this for free on - underscore.io/training/courses/essential-scala — sarveshseri
– sarveshseri, Commented Apr 15, 2020 at 6:15
your problem is you trying assign String value to x but declare x as Option[String] this is different types. try to wrap "abc": Option("abc") and after that you will need to wrap y also for comparing. Read more about option for using it correctly. — Boris Azanov
– Boris Azanov, Commented Apr 15, 2020 at 7:51

Tim · Accepted Answer · 2020-04-15 06:12:14Z

2

The type mismatch is because String and Option[String] are different types and you can't directly compare them.

You probably want this:

if (x.contains(y)) "YES" else "No"

This checks whether x has something in it (is not None) and, if so, whether that something equals y.

answered Apr 15, 2020 at 6:12

Tim

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