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So i am trying to dig into a lot more Vanilla JS and i set up an object and an empty array and i pushed the object inside the array but when i console.log my array it returns the length only. What am i doing wrong or how can i see what is inside the array?

This is my sample code

let empty = []

let exp = {
  2: 'Hey',
  28: 'Yo',
  9: 'Heyyyy!!',
  6: 'Foo'
}

let newValue = empty.push(exp)
console.log(newValue)

Now if i do not use the newValue but do this instead it seems to work:-

let empty = []

let exp = {
   2: 'Hey',
   28: 'Yo',
   9: 'Heyyyy!!',
   6: 'Foo'
}

empty.push(exp)
console.log(empty)

Why does console.log(newValue) does not return the array and the object stored inside it? i thought that i should be able to assign values to a new variable. If someone can clear it, i sure will appreciate it.

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3 Answers 3

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2

push method add the value to array we are operating on and returns the new length of array.

let newValue = empty.push(exp)

is same as. 

let newValue = empty.length ( length after pushing value )

second snippets shows the array as you're logging the actual array where as in first snippet newValue is same as length of array.

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1 Comment

ohh!!! Thanks for clearing it up!! It makes sense now!! Accepting the answer. :)
1

You are logging the return value of push, which is the length. Check the docs for more information.

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0

You could use the spread syntax in order to achieve a similar result to what you've attempted:

let empty = [];

let exp = {
  2: "Hey",
  28: "Yo",
  9: "Heyyyy!!",
  6: "Foo",
};

let newValue = [...empty, exp];
console.log(newValue);

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