How can I capture the URL from regex in Python? [duplicate]

Question

import re   
string = """position":1,"url":"https://www.flipkart.com/honor-8c-black-64-gb/p/itmfc8c4fsekrpdp?pid=MOBFC8C8FXXNHZ7C&lid=LSTMOBFC8C8FXXNHZ7CZYQGKP&marketplace=FLIPKART,"""
regex = "\w\w\w\w\w\w\w\w\W\W\d\W\W\w\w\w\W\W\W\w\w\w\w\w\W\/\/(...)\"\W"             
match = re.findall(regex, string)  
print(match)

I want to capture just the link from the above variable the output must be in this way -(https://www.flipkart.com/honor-8c-black-64-gb/p/itmfc8c4fsekrpdp?pid=MOBFC8C8FXXNHZ7C&lid=LSTMOBFC8C8FXXNHZ7CZYQGKP&marketplace=FLIPKART) while i run the above code it just gives me empty parenthesis

I think so that something is wrong with my regex so anyone please help me

THANKING IN ADVANCE.

That string looks like its part of a larger serialized data stream. Is it JSON? If so, the answer is to parse the JSON. Urls are difficult to express in a single regex. — tdelaney
– tdelaney, Commented Apr 18, 2020 at 19:57

Grajdeanu Alex · Accepted Answer · 2020-04-18 19:55:08Z

1

You have some formatting issues. Here you go (assuming this format is consistent, otherwise follow the advice from the comments):

import re

string ='"position":1,"url":"https://www.flipkart.com/honor-8c-black-64-gb/p/itmfc8c4fsekrpdp?pid=MOBFC8C8FXXNHZ7C&lid=LSTMOBFC8C8FXXNHZ7CZYQGKP&marketplace=FLIPKART"'
regex = r'\"url\":\"(.*)\"'
match = re.search(regex, string)

print(match.group(1))

answered Apr 18, 2020 at 19:55

Grajdeanu Alex

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