How to split strings using python

You can either use regex or split, here is an example using split:

s='187045_20191025_Release_UAT_1.zip'
cms_name=[s.split('_')[0], s.split('_')[-1].split('.')[0]]
print(cms_name)

This is the result:

['187045', '1']

Basically your filename is joined by _, so you want to split by that,
also obviously you want the first and last parts,

To get the first part just take the first element of the split,
the last part also has the file extension attached, so you can get rid of that by splitting on the . and taking the first part of that split.

try this:

parts = '187045_20191025_Release_UAT_1.zip'.split('_')
cms_name = parts[0]
the_one_at_the_end = parts[-1].split('.')[0]

print([cms_name, the_one_at_the_end])

Output:

['187045', '1']

text='187045_20191025_Release_UAT_1.zip'
text=text.replace('.zip','')
arr=text.split('_')
print([arr[0],arr[-1]])

Output:

['187045', '1']

Really simple:

import os
my_file_name = os.path.basename("test_x_y_1.png")
my_file_name = my_file_name.split("_")
my_file_name[len(my_file_name)-1] = my_file_name[len(my_file_name)-1].split(".")
what_you_wanna_get = list((my_file_name[0], my_file_name[len(my_file_name)-1][0]))
print(what_you_wanna_get)

The code is very basic and can be optimized but you got the spirit... Use split to separate your string everytime a "_" or a "." or whatever you want appear ;)

You can also use list unpacking

g = '187045_20191025_Release_UAT_1.zip'

first, *middle,  last = g.replace('.zip','').split('_')

print([first, last])

We replace '.zip' with nothing, split with _. This returns a list to which you can get first and last items. If you are not going to use the middle which is a list of all values in the middle, you can just do *_ as a throwaway variable

I believe unpacking would give a more elegant solution if you regularize the separators (i.e. "." as "_"):

fileName = '187045_20191025_Release_UAT_1.zip'

reqId,*_,testId,_ = fileName.replace(".","_").split("_")

output:

print([reqId,testId])

['187045', '1']

if you assign your string as an variable called a, shown below:

a = "187045_20191025_Release_UAT_1.zip"

you can get what you desire by this code below:

lis = [a.split("_")[0], a.split("_")[-1][:-4]]

which in this actually we have a.split("_") as:

a.split("_") = ['187045', '20191025', 'Release', 'UAT', '1.zip']

You can also use something like this

text='187045_20191025_Release_UAT_1.zip'
arr = text.replace('.zip', '').split('_')

>>> arr[::len(arr)-1]
['187045', '1']