Error with GuzzleHttp trying to decode a JSON string into an array in a php 7 installation

Question

I'm trying to convert a json string into an array with php.

My php version is 7.0

I'm getting this error:

PHP Fatal error: Uncaught Error: Call to undefined function GuzzleHttp\json_decode()

Here's the code with the issue:

$adjunto1 = $value['archivo']; 
$adjunto2 = json_decode($adjunto1, TRUE); //this is teh line with the error

$value['archivo'] comes from the database, and if I see inside I get:

string(155) "{"nombre":["ejemploxls"],"archivoContenido":["id.--ejemploxls--fecha-26-04-2020-10-08.xls"],"fecha":["26-04-2020-10-08"],"size":[5632],"extension":["xls"]}"

When I converted the array to a json string using json_encode(), the array looked like this:

  array(5) {
    ["name"]=>
    string(11) "ejemplo.xls"
    ["type"]=>
    string(24) "application/vnd.ms-excel"
    ["tmp_name"]=>
    string(14) "/tmp/php7M0gVS"
    ["error"]=>
    int(0)
    ["size"]=>
    int(5632)
  }

What is this error? What is GuzzleHttp?

Seems that you have some kind of implicit import of GuzzleHttp. To solve that problem let's try to add a slash before function call: $adjunto2 = \json_decode($adjunto1, TRUE);. If you want to obtain much more detailed answer, add a list of you php-imports (use), please. — Maksim Yakunin
– Maksim Yakunin, Commented Apr 26, 2020 at 14:11
Using \ got it sorted, thank you @MaksimIakunin! Please add it as an answer, so I can accept it. Why I did an implicit import of GuzzleHttp? I didn't even know about GuzzleHttp... — Rosamunda
– Rosamunda, Commented Apr 26, 2020 at 14:18

Maksim Yakunin · Accepted Answer · 2020-04-26 14:36:44Z

2

Seems that you have some kind of implicit import from GuzzleHttp.

Guzzle is an extensible PHP HTTP client.

Here is a wrapper for json_decode php-function from GuzzleHttp namespace, that may cause your problem.

As a quick soluiton just add a slash before function call:

$adjunto2 = \json_decode($adjunto1, TRUE);

If you want to obtain much more detailed answer from me, plese, add a list of you use-statements from beginning of your php-file. Also list of includes (if there is any) would be helpful. I need some more context to be more precise.

edited Apr 26, 2020 at 14:36

answered Apr 26, 2020 at 14:23

Maksim Yakunin

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Error with GuzzleHttp trying to decode a JSON string into an array in a php 7 installation

I'm getting this error:

Here's the code with the issue:

$value['archivo'] comes from the database, and if I see inside I get:

1 Answer 1

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Collectives™ on Stack Overflow

I'm getting this error:

Here's the code with the issue:

$value['archivo'] comes from the database, and if I see inside I get:

1 Answer 1

Comments

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