I have arrays like:
a = ['a', 'b', 'c']
b = [1, 2, 3]
and I would like to get:
[['a', 1], ['b', 2], ['c', 3]]
Is there some elegant (functional) way to do this, or will I have to use loops and indexes?
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1why elegant? what does not work?Nina Scholz– Nina Scholz2020-04-26 20:49:03 +00:00Commented Apr 26, 2020 at 20:49
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I think you are looking for this: stackoverflow.com/questions/22015684/…Tefek– Tefek2020-04-26 20:51:06 +00:00Commented Apr 26, 2020 at 20:51
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@493msi Thanks, couldn't find it :)Arsen– Arsen2020-04-26 20:52:59 +00:00Commented Apr 26, 2020 at 20:52
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2 Answers
Would you consider something like this "elegant"?
a.map((x, idx) => [x, b[idx]]);
answered Apr 26, 2020 at 20:51
whatamidoingwithmylife
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1 Comment
neaumusic
I'd use slightly different variable names and
i not idx but this is goodOption 1
var a = ['a', 'b', 'c']
b = [1, 2, 3];
var zip = [];
for (var i = 0; i < a.length; i++){
zip.push([a[i], b[i]]);
}
OR to use fewer lines i.e. more 'elegant' approach:
Option 2
var a = ['a', 'b', 'c']
b = [1, 2, 3];
var zip = (b, a) => b.map((k, i) => [k, a[i]]);
// Instead of the for loop
// [['a', 1], ['b', 2], ['c', 3]]
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