Getting output of a c file into a bash variable

Question

I have a c file that checks whether there is a ! in the argument given (ie ./a.out hi!) and return 0 if it does and 1 if it doesn't, which works as it's supposed to.

I need to make a bash shell file (.sh) that uses the c file to check if files in a directory contain the character, ie. if the directory has dogs!.sh fly!.c ring.txt, executing ./script.sh should return

dogs!.sh
fly!.c

But I have no idea how to do so? Can anybody help out?

I think you left an extraneous } in your c file, right by the else statement. Your if block doesn't use a bracket, so when it reaches that next one it thinks you're ending the main() routine. — Matthew P.
– Matthew P., Commented Apr 29, 2020 at 23:00

Carl Norum · Accepted Answer · 2020-04-29 23:00:39Z

3

Your compile line:

gcc includes.c

Will produce an output program called a.out. You need to run that command, not try to execute your C source as a shell script, which is what your current script is doing. Example:

ret=$(./a.out ${file})

You don't need the ret, though, since your program has no output. Just check the exit value.

if [[ $? -eq 0 ]]

Editorial note: this answer assumes that you've copy/pasted something wrong when asking this question, since your error message shows alpha.c, but that's not mentioned anywhere else. And that you fix the syntax errors in your C program, too!

answered Apr 29, 2020 at 23:00

Carl Norum

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1 Comment

choroba Over a year ago

You can also check the return value directly if a.out "$file"...

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