I have a string:
"2y20w2d2h2m2s"
I need to split it to be like that:
["2y","20w","2d","2h","2m"2s”]
I tried to use re.split but i couldnt make it work
this was my attempt:
time = re.split("s m h d w y", time)
*time is the string above
finally, I will apricate of you would help understand how to make it work
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1Do the sections you want the string to split into always start with a 2?mapf– mapf2020-05-03 15:02:20 +00:00Commented May 3, 2020 at 15:02
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a good Q that i forgot to sepcify but its not supposed to be only 2 its supposed to be any numberyotam rec– yotam rec2020-06-07 15:06:12 +00:00Commented Jun 7, 2020 at 15:06
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4 Answers
Code:
import re
time_str = "2y20w2d2h2m2s"
time = re.findall(r"(\d*\S)", time_str)
print(time)
Output:
>>> python3 test.py
['2y', '20w', '2d', '2h', '2m', '2s']
Try it online:
Comments
In case the sections you want the string to split into always start with 2, this does the trick:
string = "2y20w2d2h2m2s"
print(string.replace('2', ' 2').split())
Comments
Try:
import re
print(re.findall('(\d+[a-z])', "2y20w2d2h2m2s"))
Output
['2y', '20w', '2d', '2h', '2m', '2s']
Explanation
Regex pattern for 1 or more numbers followed by a letter
(\d+[a-z])
Comments
Being as specific as possible for your use case:
import re
s = "2y20w2d2h2m2s"
re.findall('([0-9]{1,2}[ywdhms]{1})', s)
Output: ['2y', '20w', '2d', '2h', '2m', '2s']
This produces exactly what you want with no extraneous letters or numbers with more than two digits.
