I have for example the following list:
['|', u'MOM', u'DAD', '|', u'GRAND', '|', u'MOM', u'MAX', u'JULES', '|']
and want it to be split by the "|" so the result would look like:
[[u'MOM', u'DAD'],[ u'GRAND'], [u'MOM', u'MAX', u'JULES']]
How can I do this? I only find examples of sublists on the net which need a length of the elements
>>> [list(x[1]) for x in itertools.groupby(['|', u'MOM', u'DAD', '|', u'GRAND', '|', u'MOM', u'MAX', u'JULES', '|'], lambda x: x=='|') if not x[0]]
[[u'MOM', u'DAD'], [u'GRAND'], [u'MOM', u'MAX', u'JULES']]
[list(x[1]) for x in itertools.groupby(myList, lambda x: x=='|') if not x[0]]itertools.groupby() does this very nicely...
>>> import itertools
>>> l = ['|', u'MOM', u'DAD', '|', u'GRAND', '|', u'MOM', u'MAX', u'JULES', '|']
>>> key = lambda sep: sep == '|'
>>> [list(group) for is_key, group in itertools.groupby(l, key) if not is_key]
[[u'MOM', u'DAD'], [u'GRAND'], [u'MOM', u'MAX', u'JULES']]
Simple solution using plain old for-loop (was beaten to it for the groupby solution, which BTW is better!)
seq = ['|', u'MOM', u'DAD', '|', u'GRAND', '|', u'MOM', u'MAX', u'JULES', '|']
S=[]
tmp=[]
for i in seq:
if i == '|':
S.append(tmp)
tmp = []
else:
tmp.append(i)
# Remove empty lists
while True:
try:
S.remove([])
except ValueError:
break
print S
Gives
[[u'MOM', u'DAD'], [u'GRAND'], [u'MOM', u'MAX', u'JULES']]
>>> reduce(
lambda acc,x: acc+[[]] if x=='|' else acc[:-1]+[acc[-1]+[x]],
myList,
[[]]
)
[[], ['MOM', 'DAD'], ['GRAND'], ['MOM', 'MAX', 'JULES'], []]
Of course you'd want to use itertools.groupby, though you may wish to note that my approach "correctly" puts empty lists on the ends. =)
[].split(token); the input should just leave off the '|' on the ends.