Display elements in my 2d Array in Javascript

Question

I have a post function that returns a 2d array. How would I go about displaying each of the elements in it? My code looks something like this :

$.post("/Question/GetPollQuestionsForView/", { poll_ID: pollId }, function(result) {
   //$("#CustomerList tbody").append($(result));
   var myarray = new Array()
   myarray = result;
   alert(myarray);
});

what the alert returns is "System.String[][]". How can i go about appending each of the values from my array to my div tag called #divComparativeQuestions.

If the alert shows "System.String[][]", the myarray is not an array but a string. You have to send the correct data from the server. Btw. you could just do: var myarray = result;. — Felix Kling
– Felix Kling, Commented May 29, 2011 at 9:40

Andy · Accepted Answer · 2011-05-29 09:32:37Z

1

For example:

var data = new Array();
for(var i=0;i<myarray.length;i++){
   data.push(myarray[i].join(', '));
}
$('#divComparativeQuestions').html(data.join('<br/>'));

(hope this works, not tested :), but you get the idea )

answered May 29, 2011 at 9:32

Andy

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1 Comment

Hriskesh Ashokan Over a year ago

throws an error, on data.push(myarray[i].join(', ')); " Microsoft JScript runtime error: Object doesn't support this property or method "

darkliquid · Accepted Answer · 2011-05-29 09:41:04Z

0

I'm guessing you want something like:

// given an array [[1,2],[3,4]] with a desired result of <div>1234</div>
$.post("/Question/GetPollQuestionsForView/", { poll_ID: pollId }, function(data) {
    if(data) {
        var div = $('#divComparativeQuestions');
        $.each(data, function(index, element) {
            div.append(element); // will be inner array of [1,2] or [3,4]
        }); 
    }
});

All pretty basic stuff, in this case I'm taking advantage of the fact js typically flattens array as strings without commas to get the desired out put, but if you want to delimit them items somehow or wrap them in tags or whatever, it's easy enough to work out by taking a few seconds to browse http://docs.jquery.com

answered May 29, 2011 at 9:41

darkliquid

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2 Comments

darkliquid Over a year ago

"Doesn't work" doesn't really help me fix that. How so? Syntax error? Doesn't do anything? What is the data your post to that url is meant to return?

darkliquid Over a year ago

Never mind, I didn't notice your alert is actually returning a string rather than you just describing the type. Yeah, you should change your code to return some valid JSON data or something similar ideally. The above code should operate correctly on a javascript array.

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