On Instagram, I'm using Python and Selenium to post a picture.
However, i'm a little bit lost when this new window is open : how do I'm supposed to go to the path of the file I want to post and continue ? With Selenium ? With an other Library ?
I read some responses, but can't find a good one about this (seeming simple) point. I can't use the input/"sendkey" option
Get the local path of your photo. Then upload it like you would send a key to the upload element.
dv.find_element_by_xpath("XPATH").send_keys(path of photo)
Example of use in action: Getting the local path of the photo
with os.scandir("./photos") as entries:
os.chdir("./photos")
photos = []
for entry in entries:
if entry.is_file():
print(entry)
photos.append(entry.name)
Upload it
# click on element where you have to upload
dv.find_element_by_xpath("/html/body/div[1]/div/div[1]/header/div/div[1]/div[2]/form/div[1]/span/span/span[2]").click()
# input file location from local system
dv.find_element_by_xpath("/html/body/div[5]/div/div/div[1]/div/form[1]/input").send_keys(photo)
