How can I replace the following code written in python3 with normal sort() function?
list = sorted(list, key=lambda x: x['result'], reverse=True)
NOTE: x['result'] is int
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In the future, please explain what you mean by things like "the normal sort() function". It would be more helpful to say something like "the list.sort() method" for instance.JacKeown– JacKeown2020-05-14 03:33:38 +00:00Commented May 14, 2020 at 3:33
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2 Answers
You can do exactly the same thing using list.sort(), i.e it takes in a "key" argument,
all you have to do is to change the function call on position_list into a method call.
For example:
l.sort(key=lambda x: x["result"], reverse=True)
As far as the lambda is concerned, you can just substitute it with a real function instead, but I don't think anything else can be simpler than a lambda.
P.S: Have a look at the documentation: https://docs.python.org/3/library/stdtypes.html#list.sort
Use: competition_list.sort(key=lambda x: x['result'], reverse=reversed_order). It sorts the list in place.
