Typecasting the output in Python

Question

Here in my code I am getting output something like <generator object <genexpr> and I dont know why. I tried to cast it to some tuple or list but still the same problem.

for example:
>>> 5 1000          //where n = 5 is number of points, p = 1000 the money which already exists
>>> 386 780 0       //x,y,m and we just care about m here and if m of any point is bigger than p, 
    494 160 1215    //we append the point to the list l
    313 573 1553
    216 506 750
    355 506 1630

output should be number of points '2 3 5' but I'm getting this:

<generator object <genexpr> at 0x012AB610> <generator object <genexpr> at 0x012AB5A0> <generator object <genexpr> at 0x012AB648>

My code:

import random
random.seed(42)
n, p = list(map(int, input().split()))
x = []
y = []
m = []
l = set()

for i in range(0, n):
    a1, a2, a3 = list(map(int, input().split()))
    x.append(a1)
    y.append(a2)
    m.append(a3)
points = [random.random() for _ in range(n)]
for v in m:
     if v > p:
         l.add(v(point) for point in points)

print(*l)
print(len(l))

You are using a generator expression to create generator objects... Do you know what that means? If not, I suggest not using generators — juanpa.arrivillaga
– juanpa.arrivillaga, Commented May 14, 2020 at 23:22
are you using a set on purpose too? Sets don't allow only unique values — bherbruck
– bherbruck, Commented May 14, 2020 at 23:27
@juanpa.arrivillaga yeah I know it's a generator. I am just trying to append those points which its m > p and I only found out this method. — codingbase
– codingbase, Commented May 14, 2020 at 23:30

Barmar · Accepted Answer · 2020-05-14 23:38:09Z

2

v(point) for point in points is a generator expression. You don't get the output unless you do something that iterates over it.

You should iterate over it, and add each element.

for v in m:
    if v > p:
        for point in points:
            l.add(point)

edited May 14, 2020 at 23:38

answered May 14, 2020 at 23:22

Barmar

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9 Comments

codingbase Over a year ago

I've already tried that before but I get this error ``` l.add(tuple(v(point) for point in points)) TypeError: 'int' object is not callable```

Barmar Over a year ago

That's a different problem. What is v(point) supposed to mean?

Barmar Over a year ago

Maybe you meant v[point]? I can't really follow what your code is doing.

codingbase Over a year ago

Sorry I did a mistake here, it should be point(v). it means the point of object v. I am trying to append those points which its m > p and I only found out this method. I would like to know if there's other useful methods

Barmar Over a year ago

point(v) doesn't make sense either. point is a random number, not a function.

|

Abbas · Accepted Answer · 2020-05-15 00:14:05Z

1

v(point) won't work because v is an integer, not a function. The expression v(point) for point in points is creating a generator object which is why it's not throwing an error.

It seems to me that you are trying to add the points for inputs where m is greater than p. You can do so by using enumerate:

import random
random.seed(42)
n, p = list(map(int, input().split()))
x = []
y = []
m = []
l = set()

for i in range(0, n):
    a1, a2, a3 = list(map(int, input().split()))
    x.append(a1)
    y.append(a2)
    m.append(a3)
points = [random.random() for _ in range(n)]
for idx, v in enumerate(m):
     if v > p:
         l.add(points[idx])

print(*l)
print(len(l))

edited May 15, 2020 at 0:14

answered May 15, 2020 at 0:07

Abbas

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