(Java ) Finding the largest number in an array and it's location

Question

I'm currently learning Java and while I'm able to find the largest number I'm stuck on how to find it's location. Any help would be greatly appreciated!

import java.util.Random;
public class FindingLargestValueInAnArray {
    public static void main(String[] args) {
        Random number = new Random();

        int[] array_1 = new int[10];

        int i = 0;
        for (i = 0; i < array_1.length; i++) {
            int randNum = 1 + number.nextInt(99);
            array_1[i] = randNum;
        }

        System.out.print("Array:");

        for (i = 0; i < array_1.length; i++) {
            System.out.print(" " + array_1[i]);
        }

        int largeNumb = 0;

        for (i = 0; i < array_1.length; i++) {
            if (array_1[i] > largeNumb) {
                largeNumb = array_1[i];
            }
        }

        System.out.println("\n\nThe largest value is 
            "+largeNumb);
        }
    }

Lizzzzz · Accepted Answer · 2020-05-15 06:28:08Z

1

    public class FindingLargestValueInAnArray {
        public static void main(String[] args) {
        Random number = new Random();

        int[] array_1 = new int[10];

        int i = 0;
        for (i = 0; i < array_1.length; i++) {
            int randNum = 1 + number.nextInt(99);
            array_1[i] = randNum;
        }

        System.out.print("Array:");

        for (i = 0; i < array_1.length; i++) {
            System.out.print(" " + array_1[i]);
        }

        int largeNumb = 0;
        int index = 0;

        for (i = 0; i < array_1.length; i++) {
            if (array_1[i] > largeNumb) {
                largeNumb = array_1[i];
                index = i;
            }
        }

        System.out.println("The largest value is " + largeNumb + " and it's location is" + index);
    }
}

answered May 15, 2020 at 6:28

Lizzzzz

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1 Comment

Ausamah Hobbi Over a year ago

Thank you very much!

Andreas · Accepted Answer · 2020-05-15 06:42:33Z

0

You should get an another variable for the index = 0 and then put it inside the if statement and make it equal to index = i;. After the loop ends the largest value index would be stored here.

edited May 15, 2020 at 6:42

Andreas

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answered May 15, 2020 at 6:26

YMS98

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Comments

kalina199 · Accepted Answer · 2020-05-15 06:11:47Z

0

you can make an int index=0 in the loop where you check if the number is bigger in the body of the if make infex=i. This way you will always have both the value and the index of the largest numnber.

answered May 15, 2020 at 6:11

kalina199

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Comments

ANSHUMAN YUVRAJ · Accepted Answer · 2020-05-15 07:22:32Z

import java.util.Random;

public class FindingLargestValueInAnArray {
    public static void main(String[] args) {
        Random number = new Random();

        int[] array_1 = new int[10];

        int i = 0;
        for (i = 0; i < array_1.length; i++) {
            int randNum = 1 + number.nextInt(99);
            array_1[i] = randNum;
        }

        System.out.print("Array:");

        for (i = 0; i < array_1.length; i++) {
            System.out.print(" " + array_1[i]);
        }

        int largeNumb = array_1[0];
        int index = 0;
        for (i = 1; i < array_1.length; i++) {
            if (array_1[i] > largeNumb) {
                largeNumb = array_1[i];
                index = i;
            }
        }

        System.out.println("\n\nThe largest value is :" + largeNumb + " and it's index is: " + index);
      }
}

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