val arr = List(8, 15, 22, 1, 10, 6, 18, 18, 1) arr.zipWithIndex.map(_._2) works and give me index of the elements in the list .How to access the index and the element as part of the map function
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Your map function already has the value and the index, but you are discarding the value. So it is not clear to me what is the question.Luis Miguel Mejía Suárez– Luis Miguel Mejía Suárez2020-05-19 12:53:04 +00:00Commented May 19, 2020 at 12:53
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3 Answers
val arr = List(8, 15, 22, 1, 10, 6, 18, 18, 1)
arr.zipWithIndex.map(zippedList => (zippedList._1, zippedList._2))
if you want to access the element it's ._1 and index ._2
you can also use this:
arr.zipWithIndex.map {
case (x, y) => print(x, y)
}
and so the operation on x and y what ever you want to do.
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boredmgr
Thanks Raman. I was trying to destruct the inside the parameter list itsef.
This is typically done using zipWithIndex and pattern matching:
arr.zipWithIndex.map{ case (value, index) => ??? }
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You can use partial function to deconstruct a tuple
val arr = List(8, 15, 22, 1, 10, 6, 18, 18, 1)
arr.zipWithIndex.map { case (value, index) => println(value -> index) }
