PHP if-Statement with multiple conditions

Question

How would the valid syntax be for the following if-statement?

if ($properties->offering_type === 'y' || $properties->offering_type === 'p' && $properties->sold != 'y') { 
  // echo something
} else {
}

I want to echo something when offering_type is either y or p and sold is not y

Barmar · Accepted Answer · 2020-05-22 15:00:18Z

3

&& has higher precedence than ||, so your condition is interpreted as

if ($properties->offering_type === 'y' || 
    ($properties->offering_type === 'p' && $properties->sold != 'y')) {

You need to add parentheses to group the || together.

if (($properties->offering_type === 'y' || $properties->offering_type === 'p')
    && $properties->sold != 'y') {

answered May 22, 2020 at 15:00

Barmar

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2 Comments

Kunal Raut Over a year ago

A well explained answer:).

Harish ST Over a year ago

Indeed well explained!

Harish ST · Accepted Answer · 2020-05-22 14:59:46Z

1

<?php

if ( ($properties->offering_type === 'y' || $properties->offering_type === 'p') && ($properties->sold != 'y') ) { 
  // echo something
} 
else {

}

Please note that you are using === which means the type should also be the same. And you are not doing that for the sold property (!=).

answered May 22, 2020 at 14:59

Harish ST

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