All possible substring in Python

You could do something like:

for length in range(len(string)):
    for index in range(len(string) - length):
        print(string[index:index+length+1])

Output:

a
b
c
ab
bc
abc

else one way is using the combinations

from itertools import combinations
s = 'abc'
[
    ''.join(x)
    for size in range(1, len(s) + 1)
    for x in  (combinations(s, size))
]

Out

['a', 'b', 'c', 'ab', 'ac', 'bc', 'abc']

Every substring contains a unique start index and a unique end index (which is greater than the start index). You can use two for loops to get all unique combinations of indices.

def all_substrings(s):
    all_subs = []
    for end in range(1, len(s) + 1):
        for start in range(end):
            all_subs.append(s[start:end])
    return all_subs

s = 'abc'
print(all_substrings(s)) # prints ['a', 'ab', 'b', 'abc', 'bc', 'c']

You can do like:

def subString(s):
    for i in range(len(s)):
        for j in range(i+1,len(s)+1):
            print(s[i:j])

subString("aashu") a aa aas aash aashu a as ash ashu s sh shu h hu u