We have an interface defined this way:
interface IInitialInterface {
stack: string,
overflow: {
a: string,
b: string
}[],
}
How can I create a type with only the overflow property removing the array? If I do:
type TypeSearched = IInitialInterface['overflow']
Then I get:
type TypeSearched = {
a: string,
b: string
}[]
But I want to remove the array.
Thank you.
To get the member type of an array you can drill in with ArrayType[number]. This returns the type that would be returned if you accessed that array with any number.
type TypeSearched = IInitialInterface['overflow'][number]
// { a: string; b: string; }
However, a cleaner approach would be to build the pieces from named little pieces, rather than disassembling the big piece.
interface TypeSearched {
a: string,
b: string
}
interface IInitialInterface {
stack: string,
overflow: TypeSearched[]
}
overflow property is not "typed" in this case, you can do this
interface IInitialInterface {
stack: string,
overflow: IOverflow[],
}
interface IOverflow {
a: string,
b: string
}
Then, you can refer to IOverflow of directly instead of through IInitialInterface
type TypeSearched: IOverflow;
