Adding List Data to Another List Based on Their Value

Question

I have a List:

    List<MenuItem> makanan = [
  MenuItem(
    gambarMenu: Image.asset('images/nasigoreng.jpeg'),
    namaMenu: 'Nasi Goreng',
    priceMenu: 'Rp. 15.000',
    qty: 0,
    note: 'Catatan',
  ),
  MenuItem(
    gambarMenu: Image.asset('images/mie goreng.jpeg'),
    namaMenu: 'Mie Goreng',
    priceMenu: 'Rp. 15.000',
    qty: 0,
    note: 'Catatan',
  ),
  MenuItem(
    gambarMenu: Image.asset('images/nasigoreng.jpeg'),
    namaMenu: 'Mie Kuah',
    priceMenu: 'Rp. 15.000',
    qty: 0,
    note: 'Catatan',
  ),
  MenuItem(
    gambarMenu: Image.asset('images/nasigoreng.jpeg'),
    namaMenu: 'Nasi Campur',
    priceMenu: 'Rp. 15.000',
    qty: 0,
    note: 'Catatan',
  ),
  MenuItem(
    gambarMenu: Image.asset('images/nasigoreng.jpeg'),
    namaMenu: 'Bakso Komplit',
    priceMenu: 'Rp. 15.000',
    qty: 0,
    note: 'Catatan',
  ),
];

also have Model that I want to make list from my previous list like this:

class TableOrder {
  String namaMakanan;
  int qtyMakanan;
  String noteMakanan;

  TableOrder({this.namaMakanan, this.qtyMakanan, this.noteMakanan});
}

How can I get data from previous list into new list based on their qty value, if the qty is more than 0 that data will be added into new list.

why dont you use List.where?

Mensch
– Mensch

2020-06-01 03:24:00 +00:00
Commented Jun 1, 2020 at 3:24 — Mensch
– Mensch, Commented Jun 1, 2020 at 3:24
hi @DelphiX, I am new to Dart/Flutter, can you elaborate?

Arvy Larope
– Arvy Larope

2020-06-01 03:26:37 +00:00
Commented Jun 1, 2020 at 3:26 — Arvy Larope
– Arvy Larope, Commented Jun 1, 2020 at 3:26

Yahya Ayash Luqman · Accepted Answer · 2020-06-01 03:55:17Z

1

You can use List.where and List.map like this:

final List<TableOrder> newList = makanan
  .where((item) => item.qty > 0)
  .map((item) => TableOrder(namaMakanan: item.namaMenu, ...))
  .toList();

edited Jun 1, 2020 at 3:55

answered Jun 1, 2020 at 3:38

Yahya Ayash Luqman

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1 Comment

Arvy Larope Over a year ago

this works even better, because using another model for new list instead of filtering the current model, I can able to reset the makanan list to zero without affecting the new list.

Mensch · Accepted Answer · 2020-06-01 14:39:03Z

0

use the where method of list

List<MenuItem> newMakanan = makanan.where((item) => item.qty > 0).toList();

docs here

edited Jun 1, 2020 at 14:39

answered Jun 1, 2020 at 3:31

Mensch

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1 Comment

Arvy Larope Over a year ago

thank you DelphiX, this works. but I changed a little bit List<MenuItem> newMakanan = makanan.where((i) => i.qty > 0).toList();

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