How to set php variable as value of input in html form for those input with type "file"

Question

we can set PHP variable as the value of input in HTML form like this

<input type="number" name="price" value="<?php echo $editprice;?>" >

but this doesn't work for input with type file. I try it this way

<?php
$sqlch15="SELECT image1 FROM pc where id=$idtoe";
$resultch15= mysqli_query($db, $sqlch15);
while ($row = mysqli_fetch_array($resultch15))
{
  $editimg1 = "<img src='images/"  .$row['image1']."'>";
} 
?>

<input type="file" name="image1" value = "<?php echo $editimg1;?>">

but it doesn't work what is my mistake help me.

It's not a mistake, it's just not allowed by the browser, for security reasons - you can't try to automate the user selecting a specific file, they have to that themselves manually. It's a way of ensuring the user consents to uploading that file. And anyway it makes no sense to specify $editimg1 as the file because that points to a path on the server, not on the user's machine. So even if it was allowed, your idea wouldn't work — ADyson
– ADyson, Commented Jun 4, 2020 at 15:19
what do you want to fill there, the location on the client computer, the upload location, or the raw picture ? — user1986815
– user1986815, Commented Jun 4, 2020 at 15:32

Md. Kamrul Hassan · Accepted Answer · 2020-06-04 15:38:02Z

1

The value property contains the complete path of the file. The value property of the input:file element is read-only, because of security reasons.

answered Jun 4, 2020 at 15:38

Md. Kamrul Hassan

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user1986815 · Accepted Answer · 2020-06-04 15:42:15Z

if you press that button you upload a picture into the /tmp folder of the server (or another folder designed for that)

You will create a Array variable called $_FILES['image']

[_FILES] => Array
    (
        [image1] => Array
            (
                [name] => example.png
                [type] => image/png
                [tmp_name] => /tmp/phpq0JHjV  // that is the upload folder
                [error] => 0
                [size] => 10847
            )
    )

So the only thing that would make a little sense is to fill in the name of the file

<input type="file" name="image1" value="<?=$_FILES['image']['name'];?>">

But as I said it makes no much sense because the info about the path to this file on the client is missing.

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