passing std::array variable as argument

Question

I need help in resolving an issue which i am facing .

I would want to have a function prototype which accepts two different types of argument at two instances.

For example shown below: I have a structure as shown below:

         typedef struct BufferStruct
         {
            unsigned long    BufferType;
            unsigned long    TheAddress;
          } Buffer;

I have a function named Test and this function should accept two different types of argument

  1) std::array<Buffer, 2> axBuffer; 
  2) Buffer axBuffer;

   void Test(??)/* function argument ?*/

 These are C functions and not C++.

 Can someone please help me in getting the appropriate function prototype for the function named "Test"?

 Advanced thanks.

There is no function overloading in C. It's not possible.

Thomas Sablik
– Thomas Sablik

2020-06-06 14:18:18 +00:00
Commented Jun 6, 2020 at 14:18 — Thomas Sablik
– Thomas Sablik, Commented Jun 6, 2020 at 14:18

cdhowie · Accepted Answer · 2020-06-06 14:37:03Z

6

C doesn't have function overloading. The simplest way to approach this with a single function is to take a pointer-to-Buffer and a length:

void Test(Buffer *buffer, size_t length);

When invoking this function with a single Buffer:

Buffer buf = ...;
Test(&buf, 1);

When invoking it with an std::array:

std::array<Buffer, 2> buffers = ...;
Test(buffers.data(), buffers.size());

If you want the length argument to be optional, you have two use two differently-named functions, unfortunately:

void TestOne(Buffer *);
void TestMany(Buffer *, size_t);

edited Jun 6, 2020 at 14:37

answered Jun 6, 2020 at 14:18

cdhowie

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