C++: array<> too many initializers

Question

The following code is returning the compilation error below. I'm stuck understanding how there are too many initializers. This code works using vector<X>. Does anyone know why the error is being reported and how to resolve? Thanks

#include <iostream>
#include <array>
using namespace std;

struct X {
    int x, y;
};

int main(int argc, char *argv[])
{
    array<X,2> a0 = {{0,1}, {2,3}};

    for (auto& p : a0) {
        cout << p.x << endl;
        cout << p.y << endl;
    }

    return 0;
}

Compilation:

g++ -pedantic -Wall test116.cc && ./a.out
test116.cc: In function ‘int main(int, char**)’:
test116.cc:11:34: error: too many initializers for ‘std::array<X, 2>’
     array<X,2> a0 = {{0,1}, {2,3}};

rule of thumb for std::array, if it doesn't work then add extra braces until it does — M.M
– M.M, Commented Jun 7, 2020 at 21:50
Does this answer your question? How do you initialize (through initializer lists) a multidimensional std::array in C++11? — JaMiT
– JaMiT, Commented Jun 7, 2020 at 22:58

Arthur Tacca · Accepted Answer · 2020-06-07 21:45:39Z

21

Try

array<X,2> a0 = {{{0,1}, {2,3}}};

Note the extra set of braces.

It seems a bit odd but it's this way because the only member of array is the actual array:

template <class T, size_t N>
class array {
    T val[N];
    // ...
};

The constructors are all implicitly defined so that array ends up being a trivially constructable type.

answered Jun 7, 2020 at 21:45

Arthur Tacca

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7 Comments

notaorb Over a year ago

Why are the extra braces required? Also note, I'm copying this nearly identical to Stroustrup C++ 4th Ed Page 208, which shows no errata.

Ted Lyngmo Over a year ago

Sidenote: Brace elision works too: array<X,2> a0 {0, 1, 2, 3}; (although I personally think that makes it hard to read).

M.M Over a year ago

@notaorb the language standard for braced initialization keeps changing; it might have been correct at the time of publication!

notaorb Over a year ago

The implicit construction is similar to struct Z {int x[2];}; and struct Z zz = {{0, 1}};.

Ah_bb Over a year ago

Tysm bro. u saved my assignment.

|

Vlad from Moscow · Accepted Answer · 2020-06-07 22:03:52Z

7

You may use one of the following initializations because std::array is an aggregate that contains another aggregate as its data member.

array<X,2> a0 = { { { 0, 1 }, { 2, 3 } } };
array<X,2> a0 = { 0, 1, 2, 3 };
array<X,2> a0 = { { 0, 1, 2, 3 } };
array<X,2> a0 = { { 0, 1, { 2, 3 } } };
array<X,2> a0 = { { { 0, 1 }, 2, 3 } };

answered Jun 7, 2020 at 22:03

Vlad from Moscow

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1 Comment

Ted Lyngmo Over a year ago

... and they say C++ is strict :-) Both answers got my vote. Putting names to all the different initialization versions might provide some extra value.

Crawl.W · Accepted Answer · 2022-05-06 03:00:14Z

0

I found that my problem is related to the version of g++,9.4.0 is ok and 5.4.0 not.version of g++.By the way, the version of g++ is associated with the system version generally.

answered May 6, 2022 at 3:00

Crawl.W

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