Loop through array of function names and execute all of them in a bash script

Question

I write a bash script and i have an array of function names with variable passed to them and i want to execute all of them in a loop.

but when i execute the bash script, i get this error:

a: command not found

how can i do this?

my bash script is look like this:

#!/bin/bash

functions_array=("test a" "test b" "testc")

test() {
        echo $1
}

testc() { echo "testc!"; }

for i in ${functions_array[@]}; do
        ${i}
done

fancyPants · Accepted Answer · 2020-06-08 08:15:40Z

1

You get this error because you didn't quote your variables. Therefore test a is split into two parts.

Try it like this:

#!/bin/bash

functions_array=("test a" "test b" "testc")

test() {
        echo "$1"                          # quoting here and ...
}

testc() { echo "testc!"; }

for i in "${functions_array[@]}"; do       # also here
        ${i}
done

answered Jun 8, 2020 at 8:15

fancyPants

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2 Comments

MoAtef Over a year ago

quotes is necessary just in for loop declaration.

fancyPants Over a year ago

Quotes are always a good idea. You can check your shell scripts here: shellcheck.net There it recommends the same.

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