Using OR to set parameters inside conditional | Powershell 5

Question

Essentially I need to start my conditional using by implying 3 different conditions.

If the exit code is 1 or 2 or 3 they script must do something if anything else do something else:

if ( $LASTEXITCODE -eq 1 or $LASTEXITCODE -eq 2 or $LASTEXITCODE -eq 3 or  ) {

}

What is the correct syntax for the code above?

-or is the operator. Use an else statement for the other condition — AdminOfThings
– AdminOfThings, Commented Jun 9, 2020 at 14:46
So my sample code is correct just put a dash in front of the or? — John
– John, Commented Jun 9, 2020 at 15:01
Your code will do the condition if $lastexitcode is 1, 2, or 3. Is this intended or were you looking for elseif? — Nico Nekoru
– Nico Nekoru, Commented Jun 9, 2020 at 16:44
Another approach could be if ( $LASTEXITCODE -ge 1 -and $LASTEXITCODE -le 3) — Nico Nekoru
– Nico Nekoru, Commented Jun 9, 2020 at 16:46

Mathias R. Jessen · Accepted Answer · 2020-06-09 15:21:29Z

1

The logical OR operator in PowerShell is prefixed with -, so that would be:

if($LASTEXITCODE -eq 1 -or $LASTEXITCODE -eq 2 -or $LASTEXITCODE -eq 3){

}

For a more concise way of testing for this condition you would leverage the -contains or -in containment operators:

if($LASTEXITCODE -in 1,2,3){ ... }
# or 
if(1,2,3 -contains $LASTEXITCODE){ ... }

answered Jun 9, 2020 at 15:21

Mathias R. Jessen

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Comments

RetiredGeek · Accepted Answer · 2020-06-09 15:29:58Z

0

If $LastExitCode is always greater than 0 you could just use:

If ($LastExitCode -lt 4)  {#do for 1,2,3}
Else (#do for 4+}

If $LastExitCode could be zero:

Switch ($LASTEXITCODE) {
   0                   {"Zero"}
   {1..3 -Contains $_} {"Range 1-3"}
   Default             {"Greater than 3"}
}

HTH

answered Jun 9, 2020 at 15:21

RetiredGeek

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Careful, this would also evaluate to $true for $LASTEXITCODE = 1 :)