How to convert the object of Uint8Array to string?

Question

I have same problem as this question. I see the answer but I couldn't understand how I can do it. Is there any other suggestions?

My code is:

var eccrypto = require("eccrypto");
var w,actual;
var publicKey = Buffer.from([4, 86, 82, 58, 244, 11, 140, 41, 132, 245, 184, 162, 163, 98, 49, 119, 168, 235, 252, 50, 6, 91, 147, 191, 190, 61, 65, 63, 101, 164, 132, 213, 188, 106, 26, 203, 171, 215, 240, 151, 7, 193, 10, 151, 103, 107, 1, 135, 117, 225, 5, 41, 55, 57, 18, 205, 98, 178, 82, 135, 170, 111, 188, 98, 57],'hex');

var privateKey= Buffer.from([238, 239, 199, 101, 188, 134, 13, 13, 195, 172, 125, 168, 225, 189, 72, 148, 225, 200, 127, 218, 204, 11, 150, 146, 180, 243, 195, 109, 200, 119, 50, 20],'hex');

eccrypto.encrypt(publicKey, Buffer.from("message")).then(function(encrypted) {
    console.log(encrypted)

    let encoded =JSON.stringify(encrypted)
    w=encoded;
    console.log(encoded)

    actual = JSON.parse((encoded))
    console.log(actual)
});

eccrypto.decrypt(privateKey,actual).then(function(plaintext) {
    console.log("Message to part B:", plaintext.toString()); 
});

When I use actual variable I have this error:

Uncaught (in promise) Error: Bad public key

this the output of encrypted :

this the output of encoded :

and this the output of actual "there is some things changes i think, is not it ?": thank you advance.

decrypt is expecting a Buffer where it is being given a JSON. Maybe that is why promise is failing. Try sending encrypted eccrypto.decrypt(privateKey, encrypted) — alchemist95
– alchemist95, Commented Jun 10, 2020 at 17:45
After fixing the error from encrypt, see this for the next problem — Bergi
– Bergi, Commented Jun 10, 2020 at 17:47
@alchemist95 actually this is work but i need to save encrypted at this format : let encoded =JSON.stringify(encrypted) to use it somewhere then i want to convert it again to the original format using var actual = JSON.parse((encoded)) Is my way wrong ? — norah
– norah, Commented Jun 10, 2020 at 18:18
@Bergi thank you very much, but i use async and await to handle this problem i think it works. — norah
– norah, Commented Jun 10, 2020 at 18:25
@norah Cool, it should work when you switched from .then() to await, but the code you posted in the question didn't use async/await. — Bergi
– Bergi, Commented Jun 10, 2020 at 18:29

alchemist95 · Accepted Answer · 2020-06-11 06:46:41Z

1

While parsing, you need to send a reviver function, which conditionally parses the object. If you see how encoded looks, you will understand why the reviver function needs to be written this way.

edited Jun 11, 2020 at 6:46

answered Jun 10, 2020 at 19:23

alchemist95

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7 Comments

norah Over a year ago

it does not work, actual variable it is an object, have a look to the question to understand what i mean, i updated it. thank you

alchemist95 Over a year ago

JSON.parse(JSON.stringify)) is modifying the Buffer type which is why decrypt will keep failing. In order for decrypt() to work, you need to send a Buffer type object, not a regular JSON object.

norah Over a year ago

you mean in my case i have to make it like this: JSON.parse(encrypted) ? if it yes, it give me this error : SyntaxError: Unexpected token o in JSON at position 1 .. if not, can you explain it to me further. thanks a lot.

alchemist95 Over a year ago

If I understand correctly, you want to convert encrypted into a string. Correct? Secondly, you want to be able to retrieve the encypted buffer from that string. Right?

alchemist95 Over a year ago

JSON.parse expects a string, that's why it is failing. Ideally, encoded = encrypted.toString('hex'); const actual = Buffer.from(encoded) ; should solve your problem

|

ardean · Accepted Answer · 2020-06-10 17:43:11Z

0

I think you need to remove the "hex" encoding parameter from your Buffer.from.

answered Jun 10, 2020 at 17:43

ardean

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