Converting numpy array of str to byte string

Question

I'm really new in python. I have a numpy array of str that I woud like to convert, as it is, to a bytes string.

v = np.array([['2B', '0E', '00', '00', '00', '00', '00', '00']])

Result should be:

b'\x2b\x0e\x00\x00\x00\x00\x00\x00'

I tried bytes, encode, and many other exotic solutions but without success. Could anyone help me with that, please ?

Running [v = np.array([['2B', '0E', '00', '00', '00', '00', '00', '00']]) v.tobytes()] returns [b'2\x00\x00\x00B\x00\x00\x000\x00\x00\x00E\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x000\x00\x00\x00'] — Julien
– Julien, Commented Jun 11, 2020 at 4:47

kennyvh · Accepted Answer · 2020-06-11 06:02:00Z

1

You can use bytes

bytes([int(x, 16) for x in v[0]])

Output

b'+\x0e\x00\x00\x00\x00\x00\x00'

answered Jun 11, 2020 at 6:02

kennyvh

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Comments

Red · Accepted Answer · 2020-06-11 04:45:47Z

0

Me looking at your array and the desired result suggests

that the result simply added a \x to and lower-cased each string.

Like so:

import numpy as np
v = np.array([['2B', '0E', '00', '00', '00', '00', '00', '00']])
v = '\\'+'\\x'.join([b.lower() for i in v for b in i])
print(v.encode('utf8'))

Output:

b'\\2b\\x0e\\x00\\x00\\x00\\x00\\x00\\x00'

edited Jun 11, 2020 at 4:45

answered Jun 10, 2020 at 19:57

Red

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3 Comments

Julien Over a year ago

Wenn I run your code, it returns [b'\\2b\\x0e\\x00\\x00\\x00\\x00\\x00\\x00'] ?

Red Over a year ago

The extra backslashes are only there to escape backslashes. It is actually still equivalent to it without extra backslashes. Just try print(v.encode('utf8').decode('asciil')).

Julien Over a year ago

But wenn I run [v = np.array([['2B', '0E', '00', '00', '00', '00', '00', '00']]) v = '\\'+'\\x'.join([b.lower() for i in v for b in i]) vb=v.encode('utf8') vb==b'\x2b\x0e\x00\x00\x00\x00\x00\x00'] it returns [false] ?

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