Regex matching original datetime format in python

Question

I've crafted a regex to find unique datetime formats. I want to substitute out invalid datetimes (where the month is not 1 through 12).

i.e.

10-2019  (NO MATCH)
2-2020 (NO MATCH)
19-2019 (MATCH because 2-digit is not 1-12)

I do not care about the 4-digit number. Thus, I've derived this regex: \b(0|00|1[3-9]|[2-9][0-9])\b-\d{4}

However, I'm not receiving any matches:

>>> x = '00-1421 a 15-1432'
>>> re.sub('\b(0|00|1[3-9]|[2-9][0-9])\b-\d{4}','',x)
'00-1421 a 15-1432'

Mal Sund · Accepted Answer · 2020-06-11 04:59:27Z

1

p = re.compile(r'\b(0|00|1[3-9]|[2-9]\d)-\d{4}')
x = '00-1421 a 15-1432'
p.sub('', x)

output:

' a '

answered Jun 11, 2020 at 4:59

Mal Sund

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1 Comment

Ah, I missed the \d at the end of the 2 digit block. Thanks!