Using Regex return None while the pattern is effectively present in the string [duplicate]

Question

I ma trying to lear Regex but when I ma following a tutorial the regex I wrote return None.

import re


pattern = 'lion'
string = 'Le lion est l\'animal national de l\'Inde'

mo = re.match(pattern, string)

print(mo)

#Print None

Why ? lion is present in my string

re.match requires that matches start at the beginning of the string. Use re.search instead. — Nick
– Nick, Commented Jun 11, 2020 at 8:59
@Nick Thank you for your quick and helpful replies, I figured it out that's why I suppress the post. — kely789456123
– kely789456123, Commented Jun 11, 2020 at 9:09

Sam Morgan · Accepted Answer · 2020-06-11 09:03:56Z

1

match requires that the string starts with the given pattern. I suspect you're looking for a function more like findall.

import re

pattern = r'lion'
string = 'Le lion est l\'animal national de l\'Inde'

mo = re.findall(pattern, string)

print(mo)

['lion']

answered Jun 11, 2020 at 9:03

Sam Morgan

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