I'm working on react app with redux. I want to delete multiple item from array. I write below code in my reducer which delete single item from array but i want to delete multiple item.
case DELETE_LINK:
let dltLink = state.filter(item => {
return item._id !== action.data._id
})
return {
...state,
parentFolderlinks: dltLink
};
It seems you want to filter links from state.parentFolderlinks, say you have the ids in action.data.ids, you could
case DELETE_LINK:
const parentFolderlinks = state.parentFolderlinks.filter(item => {
return !action.data.ids.includes(item._id);
});
return {
...state,
parentFolderlinks
};
return !action.data.ids.includes(item.id) would be more effective as it doesn't have to go through the whole action.data.ids array.On what basis would you like to filter items? I assume that multiple items will not have the same id.
Below example shows how we can filter multiple items in redux. In this case, foods state with items that has type as fruit and removes everything else.
// initial state with all types of foods
const initialState = {
"foods": [
{
name: "apple",
type: "fruit"
},
{
name: "orange",
type: "fruit"
},
{
name: "broccoli",
type: "vegetable"
},
{
name: "spinach",
type: "vegetable"
},
]
}
// sample reducer that shows how to delete multiple items
export default (state = initialState, { type, payload }) => {
switch (type) {
// delete multiple items that does not have type fruit
// i.e both brocolli and spinach are removed because they have type vegetable
case DELETE_ITEMS_WITHOUT_TYPE_FRUIT:
const onlyFruits = state.foods.filter(food => food.type === "fruit");
return {
...state,
foods: onlyFruits
}
}
}
you could map over the state and run it through a function that works out if you want to keep it or not (I don't know what your logic is for that) then return the array at the end
const keepThisItem =(item) => {
return item.keep
}
case DELETE_LINK:
let itemsToKeep = []
let dltLink = state.map(item => {
if(keepThisItem(item){
itemsToKeep.push(item)
}
return itemsToKeep
})
forEach method I (without a return) is what you want. Using map here would return an array of arrays to keep. Not sure this answers the op question, either