Fetching the result from Scala Array based on a condition

Question

I have the below array with me -

 var  arrayInt: Array[Int] = Array(400, 200, 20, 30, 50,1000)

Also the below condition. I need to fetch the first 2 occurrences from the array where it satisfies the condition arrayInt < int_max.

 var int_max = 100

Expected Output

Array( 20, 30)

Thanks for your comment! What should be the best practice then? — abc_spark
– abc_spark, Commented Jun 15, 2020 at 6:43

Ivan Stanislavciuc · Accepted Answer · 2020-06-15 06:48:50Z

2

You should use filter method available for all scala collections.

val arrayInt: Array[Int] = Array(400, 200, 20, 30, 50, 1000)
val filtered = arrayInt.filter(_ < 100).take(2)
println(filtered.mkString(","))

answered Jun 15, 2020 at 6:48

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Comments

Joost Papendorp · Accepted Answer · 2020-06-15 06:48:54Z

2

Filtering the array on the condition removes the too-large numbers, then taking the first two of the remaining numbers like so:

val  arrayInt: Array[Int] = Array(400, 200, 20, 30, 50,1000)
val intMax = 100

arrayInt.filter( _ < intMax ).take( 2 )

answered Jun 15, 2020 at 6:48

Joost Papendorp

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