Catch errors with Laravel API Resource

Question

I'm trying to use Laravel API Resource and handle the error message by sending a specific HTTP code

Here is my code :

public function show($id)
{

    try {
        return FruitResource::make(Fruit::find($id));
    }
    catch(Exception $e)
    {
        throw new HttpException(500, 'My custom error message');
    }
}

My try/catch is systematically ignored when I try to access the route.

I am voluntarily accessing an object that is not in the database. I have ErrorException with message Trying to get property 'id' of non-object.

I would like to be able to send my own Exception here, in case the user tries to access data that doesn't exist. And return a json error.

return response()->json(['error' => 'Custom error message'], 500]); — Ashish Rawat
– Ashish Rawat, Commented Jun 15, 2020 at 8:52
Yeah, I know that. But the problem here is that I still have an Exception before my Try/Catch — Jeremy
– Jeremy, Commented Jun 15, 2020 at 8:54
why do you want to put this model call inside try, catch when this can be handled on the compile time as well,you can just check if the there exists a row for a given id — Ashish Rawat
– Ashish Rawat, Commented Jun 15, 2020 at 8:58

Qumber · Accepted Answer · 2020-06-15 09:43:08Z

0

Try this (notice the \ before Exception):

public function show($id)
{

    try {
        return FruitResource::make(Fruit::find($id));
    }
    catch(\Exception $e)
    {
        throw new HttpException(500, 'My custom error message');
    }
}

answered Jun 15, 2020 at 9:43

Qumber

14.7k4 gold badges24 silver badges38 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Catch errors with Laravel API Resource

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related