0

So I am reading and manipulate a file with :

base_file = open(path+'/'+base_name, "r")
lines = base_file.readlines()

After this I search and find the "raw_data" start of line.

    if re.match("\s{0,100}raw_data: ",line):
        split_line = line.split("raw_data:")
        print(split_line)
        raw_string = split_line[1]

One example of raw_data is:

raw_data: "&\276!\300\307 =\277\"O\271\277vH9?j?\345?@\243\264=\350\034\345\277\260\345\033\300\023\017(@z|\273\277L\}\277\210\\031\300\213\263z\277\302\241\033\300\000\207\323\277\247Oh>j\354\215@\364\305\201\276\361+\202@t:\304\277\344\231\243@\225k\002\300vw\262\277\362\220j\300\"(\337\276\354b8\300\230\347H\300\201\320\204\300S;N\300Z0G\300>j\210\000@\034\014\220@\231\330J@\223\025\236@\006\332\230\276\227\273\n\277\353@,@\202\205\215\277\340\356\022\300/\223\035\277\331\277\362\276a\350\013@)\353\276\277v6\316\277K\326\207\300`2)\300\004\014Q\300\340\267\271\300MV\305\300\327\010\207\300j\346o\300\377\260\216\300[\332g\300\336\266\003\300\320S\272?6\300Y@\356\250\034\300\367\277&\300\335Uq>o\010&\300r\277\252\300U\314\243\300\253d\377\300"

And raw_string will be

print(raw_data)

"&\276!\300\307 =\277\"O\271\277vH9?j?\345?@\243\264=\350\034\345\277\260\345\033\300\023\017(@z|\273\277L\}\277\210\\031\300\213\263z\277\302\241\033\300\000\207\323\277\247Oh>j\354\215@\364\305\201\276\361+\202@t:\304\277\344\231\243@\225k\002\300vw\262\277\362\220j\300\"(\337\276\354b8\300\230\347H\300\201\320\204\300S;N\300Z0G\300>j\210\000@\034\014\220@\231\330J@\223\025\236@\006\332\230\276\227\273\n\277\353@,@\202\205\215\277\340\356\022\300/\223\035\277\331\277\362\276a\350\013@)\353\276\277v6\316\277K\326\207\300`2)\300\004\014Q\300\340\267\271\300MV\305\300\327\010\207\300j\346o\300\377\260\216\300[\332g\300\336\266\003\300\320S\272?6\300Y@\356\250\034\300\367\277&\300\335Uq>o\010&\300r\277\252\300U\314\243\300\253d\377\300"

If I tried to read this file I will obtain one char to one char even for escape characters. So, my question is how to transform this plain text to utf-8 string so that I can have one character when reading \300 and not 4 characters.

I tried to pass "encondig =utf-8" in open file method but does not work.

I have made the same example passing raw_data as variable and it works properly.

RAW_DATA = "&\276!\300\307 =\277\"O\271\277vH9?j?\345?@\243\264=\350\034\345\277\260\345\033\300\023\017(@z|\273\277L\\}\277\210\\\031\300\213\263z\277\302\241\033\300\000\207\323\277\247Oh>j\354\215@\364\305\201\276\361+\202@t:\304\277\344\231\243@\225k\002\300vw\262\277\362\220j\300\"(\337\276\354b8\300\230\347H\300\201\320\204\300S;N\300Z0G\300<I>>j\210\000@\034\014\220@\231\330J@\223\025\236@\006\332\230\276\227\273\n\277\353@,@\202\205\215\277\340\356\022\300/\223\035\277\331\277\362\276a\350\013@)\353\276\277v6\316\277K\326\207\300`2)\300\004\014Q\300\340\267\271\300MV\305\300\327\010\207\300j\346o\300\377\260\216\300[\332g\300\336\266\003\300\320S\272?6\300Y@\356\250\034\300\367\277&\300\335Uq>o\010&\300r\277\252\300U\314\243\300\253d\377\300"
print(f"Qnt -> {len(RAW_DATA)}") # Qnt -> 256
print(type(RAW_DATA))
at = 0
total = 0 
while at < len(RAW_DATA):
    fin = at+4
    substrin = RAW_DATA[at:fin]
    resu = FourString_float(substrin)

    at = fin

For this example \300 is only one char.

Hope someone can help me.

1 Answer 1

2

The problem is that on the read file the escape \ symbols are coming in as \, but in the example you've provided they are being evaluated as part of the numerics that follow it. ie, \276 is read as a single character.

If you run:

RAW_DATA = r"&\276!\300\307 =\277\"O\271\277vH9?j?\345?@\243\264=\350\034\345\277\260\345\033\300\023\017(@z|\273\277L\\}\277\210\\\031\300\213\263z\277\302\241\033\300\000\207\323\277\247Oh>j\354\215@\364\305\201\276\361+\202@t:\304\277\344\231\243@\225k\002\300vw\262\277\362\220j\300\"(\337\276\354b8\300\230\347H\300\201\320\204\300S;N\300Z0G\300<I>>j\210\000@\034\014\220@\231\330J@\223\025\236@\006\332\230\276\227\273\n\277\353@,@\202\205\215\277\340\356\022\300/\223\035\277\331\277\362\276a\350\013@)\353\276\277v6\316\277K\326\207\300`2)\300\004\014Q\300\340\267\271\300MV\305\300\327\010\207\300j\346o\300\377\260\216\300[\332g\300\336\266\003\300\320S\272?6\300Y@\356\250\034\300\367\277&\300\335Uq>o\010&\300r\277\252\300U\314\243\300\253d\377\300"
print(f"Qnt -> {len(RAW_DATA)}") # Qnt -> 256
print(type(RAW_DATA))
at = 0
total = 0 
while at < len(RAW_DATA):
    fin = at+4
    substrin = RAW_DATA[at:fin]
    resu = FourString_float(substrin)
    at = fin

You would should be getting the same error that you were getting originally. Notice that we are using the raw-string literal instead of regular string literal. This will ensure that the \ don't get escaped.

You would need to evaluate the RAW_DATA to force it to evaluate the \. You can do something like RAW_DATA = eval(f'"{RAW_DATA}"') or

import ast
RAW_DATA = ast.literal_eval(f'"{RAW_DATA}"')

Note, the second option is a bit more secure that doing a straight eval as you are limiting the scope of what can be executed.

Sign up to request clarification or add additional context in comments.

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.