How to delete a section of matplotlib axis

Question

I want to have a plot like the one shown in this figure:

Here is my Python3 code:

import numpy as np
import matplotlib.pyplot as plt

x = np.arange(0.1,1.1,step=0.1)
y = np.array([0.03,0.03,0.05,0.05,0.06,0.17,0.44,1.37,4.43,6.89])
err = np.array([0.02,0.03,0.05,0.06,0.07,0.23,3.61,4.70,1.2,0.7])

fig, ax = plt.subplots(figsize=(10,8))

ax.errorbar(x,y,yerr=err)

ax.spines['right'].set_visible(False)
ax.spines['top'].set_visible(False)
ax.spines['bottom'].set_position(('axes',-0.02))
ax.spines['left'].set_position(('axes',-0.02))

ax.set_xticks(np.arange(0.0,1.21,0.2))
ax.set_yticks(np.arange(0,11,2))

ax.set_xlabel('X')
ax.set_ylabel('Y')

plt.show()

From the above code, I get this plot:

If I use ax.set_ylim([0,10]) instead of ax.set_yticks(np.arange(0,11,2)), I get the following figure having truncated the error bar:

Any leads would be highly appreciated.

Maybe this demo is helpful? Spine Placement Demo

JohanC
– JohanC

2020-06-19 15:52:26 +00:00
Commented Jun 19, 2020 at 15:52 — JohanC
– JohanC, Commented Jun 19, 2020 at 15:52
There is also Parasite Axes Demo

JohanC
– JohanC

2020-06-19 16:07:11 +00:00
Commented Jun 19, 2020 at 16:07 — JohanC
– JohanC, Commented Jun 19, 2020 at 16:07

My Work · Accepted Answer · 2020-06-20 16:18:13Z

1

Use ax.spines['left'].set_bounds(0, 10).

import numpy as np
import matplotlib.pyplot as plt

x = np.arange(0.1,1.1,step=0.1)
y = np.array([0.03,0.03,0.05,0.05,0.06,0.17,0.44,1.37,4.43,6.89])
err = np.array([0.02,0.03,0.05,0.06,0.07,0.23,3.61,4.70,1.2,0.7])
fig, ax = plt.subplots(figsize=(10,8))

ax.errorbar(x,y,yerr=err)

ax.spines['right'].set_visible(False)
ax.spines['top'].set_visible(False)
ax.spines['bottom'].set_position(('axes',-0.02))
ax.spines['left'].set_bounds(0, 10)

ax.set_xticks(np.arange(0.0,1.21,0.2))
ax.set_yticks(np.arange(0,11,2))

ax.set_xlabel('X')
ax.set_ylabel('Y')

answered Jun 20, 2020 at 16:18

My Work

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